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Mathematics 16 Online
OpenStudy (anonymous):

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 +19.6t + 58.8. What is the object's maximum height? A. 58.8 B. 194.04 C. 78.4 D. 117.6

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