A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, ft, in feet, at different times t in seconds: f(t) = -16t2 + 34t + 80 The average rate of change of f(t) from t = 5 seconds to t = 7 seconds is _____ feet per second.
Hello?
@jdoe0001
\(\bf slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\implies \cfrac{f(7)-f(5)}{7-5}\impliedby \textit{rate of change}\)
When I do that I get 158
hmmm
Am I right
@jdoe0001
sorta yes but one sec should be a negative 158
Oh ok because it is falling down the building?
\(\bf \cfrac{-466-(-150)}{7-5}\implies \cfrac{-\cancel{ 316 }}{\cancel{ 2 }}\implies -158\) yeap
Ok thank you very much, can you just help me with one more question
sure... you can just post anew, if I dunno.. someone else may help and we can revise each other
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