Question

verify the expression.
4sinθ/(1-sin^2⁡〖ϴ 〗 )=2 sec^2⁡ϴ

Answer 1

recheck the question, please

Answer 2

can u write in with equation editor

Answer 3

the initial question was 1/(1-sinϴ)+1/(1+sinϴ)=2 sec^2⁡ϴ

Answer 4

the ?s are supposed to be theta

Answer 5

ok wait

Answer 6

\(\large\tt \begin{align} \color{black}{ \dfrac{1}{(1-sin\theta)}+\dfrac{1}{(1+sin\theta)}\\~\\
=\dfrac{1+sin\theta+1-sin\theta}{(1-sin^2\theta)}\\~\\
=\dfrac{2}{cos^2\theta}\\~\\
=2sec^2\theta}\end{align}\)

Answer 7

wow what the hell was i doing lol. thank you!

Answer 8

lol