OpenStudy (anonymous):

Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.

3 years ago
OpenStudy (anonymous):

you know what this looks like? if so we can find the equation easily (no one likes these conic sections problems, but they are not that hard)

3 years ago
OpenStudy (anonymous):

i have no idea how it looks, that's all I was given

3 years ago
OpenStudy (anonymous):

$$y=-1$$ is a horizontal line, and $$(0,1)$$ is a point on the y axis

3 years ago
OpenStudy (anonymous):

|dw:1414549327167:dw|

3 years ago
OpenStudy (anonymous):

the vertex of your parabola is half way between the directrix and the focus, so it is at $$(0,0)$$ the origin |dw:1414549434635:dw|

3 years ago
OpenStudy (anonymous):

since it opens up, the $$x$$ term is squared and since the vertex is $$(0,0)$$ it looks like $4py=x^2$ all you need is $$p$$

3 years ago
OpenStudy (anonymous):

p is the distance between the focus and the vertex the distance between $$(0,0)$$ and $$(0,1)$$ is 1, making your equation $4y=x^2$

3 years ago
OpenStudy (anonymous):

so its a positive 4 would it be 4x^2?

3 years ago