OpenStudy (anonymous):

Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.

3 years ago
OpenStudy (anonymous):

you know what this looks like? if so we can find the equation easily (no one likes these conic sections problems, but they are not that hard)

3 years ago
OpenStudy (anonymous):

i have no idea how it looks, that's all I was given

3 years ago
OpenStudy (anonymous):

\(y=-1\) is a horizontal line, and \((0,1)\) is a point on the y axis

3 years ago
OpenStudy (anonymous):

|dw:1414549327167:dw|

3 years ago
OpenStudy (anonymous):

the vertex of your parabola is half way between the directrix and the focus, so it is at \((0,0)\) the origin |dw:1414549434635:dw|

3 years ago
OpenStudy (anonymous):

since it opens up, the \(x\) term is squared and since the vertex is \((0,0)\) it looks like \[4py=x^2\] all you need is \(p\)

3 years ago
OpenStudy (anonymous):

p is the distance between the focus and the vertex the distance between \((0,0)\) and \((0,1)\) is 1, making your equation \[4y=x^2\]

3 years ago
OpenStudy (anonymous):

so its a positive 4 would it be 4x^2?

3 years ago
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