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Discrete Math 18 Online
OpenStudy (anonymous):

Let a, b, and c be integers with a is not equal to 0. Prove that if ab|ac, then b|c

OpenStudy (gorv):

lol u mistyped

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

am i over thinking.. let a,b,c = 2.. 22|22 = 1 then 2|2 = 1?

OpenStudy (gorv):

22|22 means ??

OpenStudy (gorv):

plzz type the exact Q

OpenStudy (anonymous):

divisible. here is the example: Example 1.1.1. The number 6 is divisible by 3, 3|6, since 6 = 3 x 2.

OpenStudy (anonymous):

hang on

OpenStudy (anonymous):

its the first execrise on top

OpenStudy (gorv):

3|6 means 6 is divisible by 3

OpenStudy (gorv):

okk

OpenStudy (anonymous):

yeah so is my answer correct?

OpenStudy (gorv):

2|2=1 yeah

OpenStudy (anonymous):

let a,b,c be 2.. 22|22 = 1 then 2|2 = 1?

OpenStudy (gorv):

lol ab means a*b if u take them 2 that mean ab=2*2=4

OpenStudy (anonymous):

ah yeah ur right

OpenStudy (gorv):

|dw:1414589503418:dw|

OpenStudy (anonymous):

does b|c needs to be equal to ab|bc?

OpenStudy (gorv):

what are the values you have take for a , b , c

OpenStudy (anonymous):

i would use 1 for a then b|c would be equal to ab|bc

OpenStudy (gorv):

|dw:1414589626931:dw|

OpenStudy (gorv):

what is the exact Q given to you post that..so i can help u well

OpenStudy (anonymous):

let a = 1, b and c = 2.. 2|2 = 1 then 2|2 = 1

OpenStudy (anonymous):

i posted the link

OpenStudy (gorv):

u r considering by yourself ??

OpenStudy (anonymous):

im not sure how to answer it

OpenStudy (gorv):

in pdf which one??

OpenStudy (anonymous):

first execrise on top

OpenStudy (anonymous):

1.1.1

OpenStudy (gorv):

wait let me check

OpenStudy (gorv):

ohh ...ab|ac means if ab divide ac

OpenStudy (anonymous):

yeah so let a =1, b and c = 2.... 2|2 = 1 then 2|2 =1

OpenStudy (gorv):

|dw:1414589985672:dw|

OpenStudy (gorv):

which means b divide c and we can write it as b|c

OpenStudy (anonymous):

sorry my bad

OpenStudy (anonymous):

does ab|ac needs to be equal to b|c?

OpenStudy (gorv):

|dw:1414590202442:dw|

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