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Mathematics 11 Online
OpenStudy (samanthagreer):

What is the solution to the equation ? c =

OpenStudy (shinalcantara):

\[\frac{ 3 }{ 4 }(4c + 16) = 2c + 9\] cross multiply 4 to the right side and distribute 3 to the quantity \[3(4c + 16) = 4(2c + 9)\] \[12c + 48 = 8c + 36\] \[12c - 8c = 36 - 48\] \[4c = -12\] \[c = -3\]

OpenStudy (samanthagreer):

What is the solution to the equation ? m =

OpenStudy (samanthagreer):

Which answer best describes the solution to the equation −12j + 4 = −4 – 12j? A. one solution B. no solution C. an infinite number of solutions D. j = 3

OpenStudy (samanthagreer):

Which answer describes the solution to each equation?

OpenStudy (shinalcantara):

\[-5 = \frac{ 8m + 12 }{ 4 }\] cross multiply 4 -5(4) = 8m + 12 -20 = 8m + 12 8m = -20 -12 8m = -32 m = -4

OpenStudy (shinalcantara):

O_O

OpenStudy (shinalcantara):

-12j + 4 = -4 - 12j -12j + 12j = -4 - 4 0 is not equal to -8 there's no solution

OpenStudy (shinalcantara):

2x + 6 - x = 1/3(3x + 18) 2x - x + 6 = x + 6 x + 6 = x + 6 since they are equal, there's infinite solution. whatever values of x you plug in will be true to the equation

OpenStudy (shinalcantara):

\[\frac{ 1 }{ 8 } x + 7 = 19\] find LCD \[\frac{ x + 8(7) }{ 8 } = 19\] \[x +56 = 19(8)\] \[x = 152 - 56\] \[x = 96\] the equation is having one solution

OpenStudy (shinalcantara):

\[\frac{ 3x + 3 }{ 3 } = x + 1\] simplify \[x + 1= x+ 1\] since left and right are identical then it has infinite solution

OpenStudy (shinalcantara):

3 + 7x +6 = 2x + 5 + 5x 7x + 9 = 7x + 5 7x - 7x = 5 - 9 0 is not equal to -4 therefore there's no solution

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