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Three runners A,B and C run a race, with runner A finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?
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A. 36m B. 48m C. 60m D. 72m
@mathmath333 D.
@SithsAndGiggles
If \(x\) is the length of the race, then\[\frac{x-12}{x-18}=\frac{12}{10}\]
got it it is \(\large \dfrac{ x−12}{x−18}=\dfrac{x}{x−8}\) thnks
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