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Mathematics 27 Online
OpenStudy (anonymous):

What is the equation of the quadratic graph with a focus of (3, −1) and a directrix of y = 1? f(x) = −one fourth (x − 3)2 + 1 f(x) = −one fourth (x − 3)2 f(x) = one fourth (x − 3)2 + 1 <----- MY ANSWER f(x) = one fourth (x − 3)2 Can anyone please check if my answer is right? @mathstudent55 @SolomonZelman @texaschic101 @robtobey @kropot72 @paki @skullpatrol @sammixboo

OpenStudy (anonymous):

@anonymous_user PLEASE CHECK THIS FOR ME!

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (anonymous):

@mathmath333

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

Did i get it right? @mathstudent55

OpenStudy (mathstudent55):

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