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Mathematics 6 Online
OpenStudy (anonymous):

verify the identity. tanxcox/cscx = sinx

geerky42 (geerky42):

Just remember that \(\tan x = \dfrac{\sin x}{\cos x}\), \(\cot x = \dfrac{\cos x}{\sin x}\)and \(\csc x = \dfrac{1}{\sin x}\) So you cancel \(\tan x\) and \(\cot x\), leave you \(\dfrac{1}{\csc x}\) I'm sure you can handle the rest.

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