A manufacturing unit currently operates at 80 percent of its capacity. The profit function for the unit at the optimum output, x, is given by p(x) = -0.1x^2 + 80x − 60. If the function f(x) models the current capacity of the unit, the composite function giving the unit's current profit function is a.f(p(x))=-0.064x^2+6.4x-60 b.p(f(x))=-0.64x^2+0.64x-60 c.p(f(x))=-0.064x^2+64x-60 d.p(f(x))=-0.64x^2+6.4x-60 e.f(p(x))=-0.064x^2+64x-60 If the optimum output is 500 units, the current profit is $ a.15,400 b.15,940 c.16,060 d.16,600
HELP ME!!!!
@PRAETORIAN.10 @superhelp101
@TheSmartOne
@SolomonZelman :)
@perl
give me a minute to read this
f(x) is not given?
@cody7744
@ganeshie8
@thomaster
here a pic of the original problem just in case i have made an error...but really? so there is nothing i can do?
is there anything i can do?
@satellite73
@zepdrix
@robtobey
The struggle is real -_-
I will try to help
there is a lot of strange english here
optimum capacity , what does that mean?
not sure either but im googling to see what is it
do you have an online book, where did this question come from
it looks like business calc
The production capacity at which cost per unit is minimized. For a production system that shows economies of scale, this is usually the point at which the marginal cost of producing one extra unit equals the average cost of producing one unit
is from a test im taking online
can i see some questions from the test
i wish..i cant go back to previous questions, once you answere it cant go back too see..which sucks cause u cant fix
is this business calculus?
im stuck in that question
@superhelp101
no is college algebra..well thats what they call it in my school
is really hard -_-
whats the name of the book, let me see if i can torrent it
i might be able to help if i can see similar questions, and get the jargon down
no i dont use a book :/
but is ok..i ask my teacher tomorrow and see what goin on
evrything is online and the class is online also..no books sorry
can i log in and read your online notes
is alright im goin stop right here cause im tired been here since i got from school at 3pm and nobody been able to solve this problem.....imma try to get some help tomorrow when i find out i tell you what was the issue ;)
ok thanks , let us know . also there might be a way to post your online notes without having to login to your account. let me know
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