Question

find 3 consecutive positive integers such that the sum of the first and 4 times the third is 147 less than the square of the second

Answer 1

wow, your math teacher must hate you
we can start with
\[x+4(x+2)=(x+1)^2-147\] think

Answer 2

just a min

Answer 3

i made the first \(x\) so the third is \(x+2\) and the second is \(x+1\)

Answer 4

yes i understand

Answer 5

x=-11 and x=14?