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Can someone plug these 2 x values for me and tell me the result? x = pi/6, 11pi/6
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\[y=\sqrt{3} x+2 \cos x\]
they invented calculators for this
wolfram will give you exact answer
The answer looked a bit sketchy.
what was the original question, that might help
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how did you come to this expression,
I had to find the derivative of y=sqrt3 x + 2 cos x and then find which points the horizontal tangent lines occur.
If that makes sense.
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