find all solutions to 2sin2x-radical3=0
well flip flop that equation around a bit!
as in?
try to think of it as a puzzle of pieces you already know: \[\sqrt{3}\] needs what to match something of a 30-60-90 triangle?
so i would use the 60 degree triangle?
alrighty! thank you! i appreciate it!
could you help me zepdrix?
Do you still need help on this one?
haha yeah…
Did you move the sqrt{3} to the other side, and divide by...
then divide by 2
yeah i did that
then what identiy do i use for sin2x?
\[\sin2x = \sqrt{3}/2\] and the part you might be caught on is the identity...right!
yeah…thats the struggle.
2sinxcosx = sin2x
But it'd be easier just to know a property of the sinx function: http://upload.wikimedia.org/math/5/0/1/5014f43480bf84023f32b2d6059b0052.png
pretend it's just sinx = \[\sqrt{3}/2\]
right i got that
so for that x would equal? Anyway, I have to go. ask people by putting @ before their name
so would it just be pie/3+2pie n?
ouh alrighty thanks!
www.youtube.com/watch?v=z02AsqFuUnE
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