Question

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Solve 2x^2 + 3x + 6 = 0. Round solutions to the nearest hundredth.

x ≈ -2.64 and x ≈ 1.14

x ≈ -1.14 and x ≈ 2.64

No real solutions

x ≈ -1.11 and x ≈ -4.89

Answer 1

@timo86m

Answer 2

Use the quadratic formula.

Answer 3

would I just plug in the values for x in my equation?

Answer 4

2x^2 + 3x + 6 = 0 -> x^2 + 1.5x + 3 = 0 -> x^2 + 1.5x = -3
-> x^2 + 1.5x + 2.25 = -3 + 2.25 Thus no real solutions.

Answer 5

just a prove, using completing the square, without even completing anything.

Answer 6

okay, Thank you very much :)

Answer 7

YW