Question

:)

Answer 1

@marshallinwashington

Answer 2

\[\frac{ QS }{ QP }=\frac{ QP }{ QR }\]\[\frac{ 3 }{ QP}=\frac{ QP }{ 27 }\]\[(QP)^{2}=81\]\[QP=\sqrt{81}\]\[QP=9\]\[(PS)^{2}+3^{2}=(9)^{2}\]\[(PS)^{2}=72\]\[PS=\sqrt{72}\]So \[x=9\]\[y=\sqrt{72}\]

Answer 3

thnx