a ball is thrown onto the air with an upward velocity of 32 feet per second. its height h, in feet after t seconds is given by the function h(t)=-16t^2+32t+6. what is the balls maximum height? how long does it take the ball the reach the maximum height? round tho the nearest hundredth if necessary.
-reaches a maximum height of 22 feet after 1.00 seconds
-reaches a maximum height of 22 feet after 2.00
-reaches a maximum height of 44 feet after 2.17 seconds
-reaches a maximum height of 11 feet after 2.17 seconds

Question

perl · Answer

you can use the formula  t = -b/(2a)

perl · Answer

that will give you the time when it reaches maximum height

anonymous · Answer

im guessing C just because its to early for math

anonymous · Answer

and iv tryed 7 times