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OpenStudy (anonymous):

Two charged particles exert an electrostatic force of 4.8 N on each other. What will the magnitude of electrostatic force be if the distance between the two charged particles is reduced to one half of the original distance?

OpenStudy (sidsiddhartha):

|dw:1414766497818:dw| consider these two charges are separated by a distence d and force exerted is F then according to coulombs law \[F=K*\frac{ q_1q_2 }{ d^2 }\]

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