Question

can anyone help me with this problem?
6^2x+6^x-90=0
im confused on how to start it, would you use the quadratic equation???

Answer 1

gotta use logs :D

Answer 2

(6^x)^2 + (6^x) - 90 = 0

Answer 3

this has the form
u^2 + u - 90 = 0

Answer 4

( u - 9 ) ( u + 10)

Answer 5

now plug in , I substituted 6^x for u

Answer 6

(6^x - 9 ) (6^x + 10) =0

Answer 7

now use zero product property

Answer 8

6^x - 9 = 0 or 6^x + 10 = 0

Answer 9

oh okay thank you! @perl