Question

Prove that in y^3=x, y is a function of x in the reals

Answer 1

couldn't you use the vertical line test?

Answer 2

y is the function of x
look at here
y is the domain and x is the range

we suppose y is a any real number
and x is also real number
when we put ''1'' in the place of y then it give us
x=1
and when y=2
then
2^3 =x
8=x
8 is also real number
so now we put sqrt 2 in the place of y
then x = ( sqrt 2)^3
so these number showing that when we put real number at the place of y , we will get x which is also real number

Answer 3

if u have any problem then ask
i will try my best