Question

A father can do a job as fast as his 2 sons working together. If one son does the job in 3 hours and the other in 6 hours, how many hours does it take the father to do the job?

Answer 1

I am in need of the steps to find it...

Answer 2

let 't' be the time needed for the job to be completed
since you are given the rates of the two sons as:
son1:1/3
son2:1/6
then the time for the father to finish the job would be:
\[\frac{ 1 }{ 3 }t + \frac{ 1 }{ 6 }t = 1\]
\[\frac{ 2t +t }{ 6 } = 1\]
\[\frac{ 3t }{ 6 } = 1\]
\[t = 2hours\]

Answer 3

Thanks a lot for ur prompt reply... :)