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Mathematics 14 Online
OpenStudy (meganamerald):

How do I factor 4x^2-25 ??

OpenStudy (cwrw238):

notice you have 2 perfect squares 4x^2 and 25 this is the difference of 2 squares and the identity is a^2 - b^2 = (a + b((a - b)

OpenStudy (cwrw238):

so you need to find a and b that is take the square roots of 4x^2 and of 25 sand insert them in the identity

OpenStudy (cwrw238):

square root of 4x^2 is 2x and of 25 is ?

OpenStudy (meganamerald):

Square root of 25 is 5

OpenStudy (cwrw238):

right so (a + b)(a - b) becomes (2x + 5)(2x - 5) and thats it

OpenStudy (meganamerald):

Awesome thank you :)

OpenStudy (cwrw238):

yw

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