Question

Help with a graphing hyperbola problem?

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Answer 1

https://www.desmos.com/calculator/x9tbukq5dj

Answer 2

so for vertices its (-10,0) and (10,0)?

Answer 3

umm ... no?

Answer 4

then?

Answer 5

what are co-vertices?

Answer 6

\[
\frac{y^2}{25} - \frac{x^2}{81} = 1 \\
\frac{y^2}{5^2} - \frac{x^2}{9^2} = 1 \\
\text{Compare it to: }\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 \\
a = 5; ~~ b = 9; ~~ h = 0; ~~ k = 0 \\
\text{Vertices: } (h, k\pm a) \\
\text{Co-Vertices: } (h\pm b, k) \\
\text{Center: } (h, k) \\
\]

Answer 7

\[{y^2 \over a^2}-{x^2 \over b^2}=1\]

vertex: \((0,\pm a)\)