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Mathematics 14 Online
OpenStudy (anonymous):

How to find the derivative of x^2y^3 - 3xy+x+y^2=4

OpenStudy (cwrw238):

implicit differentiation treat y as a function of x and apply the product and chain rules:- x^2 * 3y^2* dy/dx + 2x*y^3 - 3x*dy/dx + 3y + 1 + 2y*dy/dx = 0 now make dy/dx the subject

OpenStudy (cwrw238):

do you see how i got that?

OpenStudy (anonymous):

yes thank you for you help

OpenStudy (cwrw238):

yw

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