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Mathematics 15 Online
OpenStudy (anonymous):

How look diagrams of y=sin²x+cos²x ; y=sin²x-cos²x ; y=sinx*cosx ?

OpenStudy (sidsiddhartha):

ok sin^2x+cos^2x=1 right? so if u plot this |dw:1414952093858:dw| just a constant function with unity value

OpenStudy (sidsiddhartha):

ok?

OpenStudy (anonymous):

ok

OpenStudy (sidsiddhartha):

now for the second function -- do know this identity \[\cos2x=\cos^2x-\sin^2x\]

OpenStudy (sidsiddhartha):

then \[-\cos2x=\sin^2x-\cos^2x\] right?

OpenStudy (anonymous):

yep

OpenStudy (sidsiddhartha):

so we have to plot (-cos2x) right?

OpenStudy (anonymous):

yes

OpenStudy (sidsiddhartha):

now cos(2x) looks like this |dw:1414952514657:dw|

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