Question

If I'm writing the given (total) area as an integral of the area above the x axis and below y = 4x - x^2, would the answer be the integral (4x - x^2)dx for [0,4]?

Answer 1

y=x(4-x)
zeros are 4 and 0
not the negative in front of the x^2 means the parabola is open down

that curve is above the x-axis between 0 and 4
so yes would you have there is the area between the x-axis and the curve on [0,4]