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GIVING MEDALS AND FAN! Find the vertex, focus, directrix, and focal width of the parabola. -1/12x^2= y
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@sangya21 @hartnn @aum @ganeshie8 @ZeldaOfHyrule
-1/12 x^2=y or, x^2=-12y This is a parabola of the fourth standard. It can be compared to x^2=-4ay So, -4a=-12 a=3 Vertex C(0,0) Focus F(0,-a)= F(0,-3) Directrix: y+3=0
so is the vertex -3?
@Navket_Jha ?
No, The vertex is a point. and according to this question its the origin
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