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A particle moves along the x-axis so that at any time t, measured in seconds, its position is given by s(t) = sin(t) − 4cos(2t), measured in feet. What is the acceleration of the particle at time t = π seconds?
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Take the derivative two times to get acceleration, and then plug in \[\pi\]. First derivative gives you velocity, and derivative of velocity gives you acceleration
Ok so what do i get as the answer
what did you get for s''(t) ?
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