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Help with exponential fractions
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Let f(x) = e^x and gf(x) = 2^x . For all x > 0, f(x) > g(x).
is this false?
hmm what's \(\Large \bf e \ ?\) anyway?
does gf(x)=2^x?
or did you mean g(x)=2^x?
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Check it with a fractional exponent.
and also joe asks a good question :) he is asking you what you think e is
sorry i meant g(x) aha
e ≈ 2.71828
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so... what do you think then... which value would be bigger for x > 0 \(\bf \large 2.71828^x\quad or\quad 2^x ?\)
2.7^x
yeap
false then? since f(x)<g(x)
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