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Find the number of different selections of 4 letters of the word AGGREGATE which contain exactly 2 Gs or exactly 3 Gs.
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AGGREGATE there are 9 elements total, and when we break then into common sets: 2: AA 3: GGG 1: R 2: EE 1: T we have a general counting rule that we can apply to this: given n elements, and multiple parts (a,b,c,...,k): \[\frac{n!}{a!~b!~c!~...~k!}\]
so im thinking, if we remove the Gs to start with we have:\[\frac{(9-3)!}{2!\cancel{3!}1!2!1!}\]distinct ways to organize the other parts.
but thats as far as my thoughts have taken me so far
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