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Mathematics 22 Online
OpenStudy (anonymous):

Help Medal Giving and will fan

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 @amistre64

OpenStudy (amistre64):

the sum of all the possible outcomes that have at least a yellow in them

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

5/9

OpenStudy (amistre64):

think of it this way .. if you want the only option that doesnt have a yellow in it is: red red the sum of all possible outcomes is 1 soo 1 - (red red) = (at least a yellow)

OpenStudy (amistre64):

the sideways page is making it hard to orient this for me

OpenStudy (anonymous):

1 sec

OpenStudy (anonymous):

OpenStudy (amistre64):

your tree looks fine now so our outcomes are: rr ry yr yy and at least 1 means that we have 1 or 2 ys in it. rr + ry + yr + yy = 1 ry + yr + yy = 1 - rr

OpenStudy (amistre64):

what is the probability of rr?

OpenStudy (anonymous):

1/4

OpenStudy (amistre64):

P(rr) = 7/10 * 6/9

OpenStudy (anonymous):

so, 42/90

OpenStudy (amistre64):

yeah, so 1 - 42/90 should give us what we need

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