Question

Simplify
5 log2 k-8 log2 m+10 log2 n

Answer 1

@StudyGurl14

Answer 2

@mathmale

Answer 3

\[5 \log_{2} k - 8 \log_{2} m + 10\log_{2} n\]
using power rule of logarithm
\[a \log b = \log b^a\]
\[\log_{2} k^5 - \log_{2} m^8 + \log_{2} n^{10}\]
now taking exponential we have,
\[ k^5 - m^8 + n^{10}\]

Answer 4

is it log 2 k^5n^10/m^8

Answer 5

@sangya21

Answer 6

Sorry I forgot sign convention
\[k^5/ m^8*n^{10}\]

Answer 7

thank you!

Answer 8

mention not.