Question

3c^2+10c+8 factor

Answer 1

Simplifying
3c2 + 10c + 8

Reorder the terms:
8 + 10c + 3c2

Factor a trinomial.
(2 + c)(4 + 3c)

Final result:
(2 + c)(4 + 3c)

Answer 2

Step by step solution :

Step 1 :

Simplify 3c2+10c + 8
Trying to factor by splitting the middle term

1.1 Factoring 3c2+10c+8

The first term is, 3c2 its coefficient is 3 .
The middle term is, +10c its coefficient is 10 .
The last term, "the constant", is +8

Step-1 : Multiply the coefficient of the first term by the constant 3 • 8 = 24

Step-2 : Find two factors of 24 whose sum equals the coefficient of the middle term, which is 10 .

-24 + -1 = -25
-12 + -2 = -14
-8 + -3 = -11
-6 + -4 = -10
-4 + -6 = -10
-3 + -8 = -11
-2 + -12 = -14
-1 + -24 = -25
1 + 24 = 25
2 + 12 = 14
3 + 8 = 11
4 + 6 = 10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 4 and 6
3c2 + 4c + 6c + 8

Step-4 : Add up the first 2 terms, pulling out like factors :
c • (3c+4)
Add up the last 2 terms, pulling out common factors :
2 • (3c+4)
Step-5 : Add up the four terms of step 4 :
(c+2) • (3c+4)
Which is the desired factorization

Final result :

(3c + 4) • (c + 2)

http://www.tiger-algebra.com/drill/3c~2_10c_8/