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What is the value of the summation ∑i=1n(2i2+i−8)? 2(n + 1)(2n + 1) + 3(n + 1) − 48 n6 [2( n + 1)(2 n + 1) + 3( n + 1) − 48] (n + 1)(2n + 1) + 3(n+1)2 − 48 n(2n+1)6 + n(n+1)2 − 48n
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