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Let f(x) = x^3 - 2x^2 + 5x - 1, and let g be the inverse function of f. What is the value of g' (9)?
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first \[(f^{-1})'(x)=\frac{1}{f'(f^{-1}(x))}\]
so first we need to find \[f^{-1}(9)=x \\ f(x)=9\] what value of x makes x^3-2x^2+5x-1 ,9?
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