Question

MEDAL!!!! PLEASE HELP!~!@!!
6, Name the minor arc and find its measure.
A. arc ADB;186*
B. arc AB;186*
C. arc ADB;174*
D. arc AB;174*
I thought the answer was A but it says minor arc? So my answer is now D?

Answer 1

D is correct

Answer 2

thanks :) Mind helping with another?

Answer 3

Sure

Answer 4

3. The figure below are similar
What are a) the ratio of the perimeters are b)the ratio of the areas of the larger figure to the smaller figure? The figures are not drawn to scale.
A. 5/2 and 25/4
B. 5/2 and 6/4
C. 7/2 and 25/4
D. 7/2 and 7/4

Answer 5

The ratio of the perimeters would be
\(\large\frac{30}{12}\)
How would you simplify that fraction?

Answer 6

15/6

Answer 7

yes, but it can be simplified further

Answer 8

7/3?

Answer 9

No...
\(\Large\frac{15}{6}\rightarrow\frac{15\div3}{6\div3}\rightarrow\frac{5}{2}\)

Answer 10

oh now I see how about the second part?

Answer 11

for the second part, take that ratio up there^ and square it
\(\Large(\frac{5}{2})^2\)

Answer 12

\(\large\rightarrow\Large\frac{5^2}{2^2}\rightarrow\frac{25}{4}\)

Answer 13

A is the answer :) thanks

Answer 14

anytime :)