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help with quadratics!!
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write a quadratic equation that has a vertex at (4,-15)
@aum
@jdoe0001
\(\large {\begin{array}{llll} (y-{\color{blue}{ k}})^2=4p(x-{\color{brown}{ h}}) \\ (x-{\color{brown}{ h}})^2=4p(y-{\color{blue}{ k}})\\ y=(x-{\color{brown}{ h}})^2+{\color{blue}{ k}}\\ x=(y-{\color{blue}{ k}})^2+{\color{brown}{ h}} \end{array} \qquad \begin{array}{llll} vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\\ \end{array} }\)
this confuses me
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pick any of the vertex quadratic forms
hmm? you;'re given the vertex coordinates already, so just plug and chug :)
wait i think i got it
i got (x-4)^2-15
yeap that'd be a quadratic with a vertex at (4, -15)
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