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OpenStudy (ineedhelp10):
HELP ASAP!!!
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OpenStudy (ineedhelp10):
Given the expression x^2+4x+11, what values of h and k would make the expression (x-h)^2+k equivalent to the given expression?
OpenStudy (ineedhelp10):
@e.mccormick
OpenStudy (ineedhelp10):
@Compassionate
OpenStudy (ineedhelp10):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
to find h, use the formula
h = -b/(2a)
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jimthompson5910 (jim_thompson5910):
x^2+4x+11 is really 1x^2+4x+11
1x^2+4x+11 is in the form ax^2+bx+c where a = 1, b = 4, c = 11
jimthompson5910 (jim_thompson5910):
If you let f(x) = x^2+4x+11
then k = f(h)
OpenStudy (ineedhelp10):
Ok so then after that, what will the next step be
jimthompson5910 (jim_thompson5910):
I stated all of the steps in a condensed form more or less
jimthompson5910 (jim_thompson5910):
are you able to find h?
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OpenStudy (ineedhelp10):
i got -2
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
how about k?
OpenStudy (ineedhelp10):
7
jimthompson5910 (jim_thompson5910):
correct
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jimthompson5910 (jim_thompson5910):
(x-h)^2+k
then turns into what?
OpenStudy (ineedhelp10):
turns into (x-4)+7
jimthompson5910 (jim_thompson5910):
you're missing something
jimthompson5910 (jim_thompson5910):
and remember you found that h = -2
jimthompson5910 (jim_thompson5910):
h isn't 4
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OpenStudy (ineedhelp10):
oh the square!
jimthompson5910 (jim_thompson5910):
(x-h)^2+k turns into (x-(-2))^2+7 which becomes (x+2)^2 + 7
OpenStudy (ineedhelp10):
ahhh ok i see my mistake nvm it makes sense! thanky uo!
jimthompson5910 (jim_thompson5910):
np
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