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Mathematics 21 Online
OpenStudy (ineedhelp10):

HELP ASAP!!!

OpenStudy (ineedhelp10):

Given the expression x^2+4x+11, what values of h and k would make the expression (x-h)^2+k equivalent to the given expression?

OpenStudy (ineedhelp10):

@e.mccormick

OpenStudy (ineedhelp10):

@Compassionate

OpenStudy (ineedhelp10):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

to find h, use the formula h = -b/(2a)

jimthompson5910 (jim_thompson5910):

x^2+4x+11 is really 1x^2+4x+11 1x^2+4x+11 is in the form ax^2+bx+c where a = 1, b = 4, c = 11

jimthompson5910 (jim_thompson5910):

If you let f(x) = x^2+4x+11 then k = f(h)

OpenStudy (ineedhelp10):

Ok so then after that, what will the next step be

jimthompson5910 (jim_thompson5910):

I stated all of the steps in a condensed form more or less

jimthompson5910 (jim_thompson5910):

are you able to find h?

OpenStudy (ineedhelp10):

i got -2

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

how about k?

OpenStudy (ineedhelp10):

7

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

(x-h)^2+k then turns into what?

OpenStudy (ineedhelp10):

turns into (x-4)+7

jimthompson5910 (jim_thompson5910):

you're missing something

jimthompson5910 (jim_thompson5910):

and remember you found that h = -2

jimthompson5910 (jim_thompson5910):

h isn't 4

OpenStudy (ineedhelp10):

oh the square!

jimthompson5910 (jim_thompson5910):

(x-h)^2+k turns into (x-(-2))^2+7 which becomes (x+2)^2 + 7

OpenStudy (ineedhelp10):

ahhh ok i see my mistake nvm it makes sense! thanky uo!

jimthompson5910 (jim_thompson5910):

np

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