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Find the area of a triangle whose base is 2√3 in. and height is 3√3 in. 9 in.² 18 in.²
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\(\Large\frac{2\sqrt{3}(3\sqrt{3})}{2}\tt =~the~answer\)
9?
\(\Large\tt\color{blue}{CORRECT!}\)
thnx:)
anytime \(\Large\ddot\smile\)
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