Question

Find the area of a triangle whose base is 2√3 in. and height is 3√3 in.


9 in.²

18 in.²

Answer 1

\(\Large\frac{2\sqrt{3}(3\sqrt{3})}{2}\tt =~the~answer\)

Answer 2

9?

Answer 3

\(\Large\tt\color{blue}{CORRECT!}\)

Answer 4

thnx:)

Answer 5

anytime \(\Large\ddot\smile\)