Question

square root of 2 sin (x-π/4)+1=0 for 0≤x≤3π

Answer 1

\(\huge \rm 2sin(x-\pi/4)+1=0\\
\huge sin(x-\pi/4)=-1/\sqrt{2}=-\sqrt{2}/2\)

Answer 2

try to solve it now

Answer 3

what angles btw 0 and 3pi give -root2/2? that what you need to find first

Answer 4

135 degrees =3pi/4

Answer 5

225 degrees =5pi/4

Answer 6

thanks i know what to do from here

Answer 7

yes correct! good luck

Answer 8

you are welcome