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solve the equations: -5y-9=-(y-1) 3y+20=3+2y
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Are you asking two questions? For first equation, distribute -1 on right side. You should have \(-5y-9 = -y+1\) Now add both sides by y: \(-5y-9 \color{red}{+y}= -y+1\color{red}{+y}\) \(-4y-9 = \cancel{-y}+1+\cancel{y}\) \(-4y-9 = 1\) See how I approach this problem? Can you do the rest?
Yes two different questions
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