Help me pleaseeee??????
Ok, what do you need help with?
remember that divided by fraction is same as multiplied by its reciprocal. So you should do that, then you can see that \((5x^2-1)\) should be cancelled.
oh yea
@geerky42 i think its D am i right?
Really? What happened to \(x+2\) and \(x-2\)?
they would cancle eachother out right cause -2+ 2 would be 0 and you would just be left with x
None, that's not how it should be. you have two different factors, which is x-2 and x+2 you cannot cancel factors out, unless they are same. \(\dfrac{x+2}{x-2} \neq\dfrac{x}{x}=1\)
oh okay so what would it be
What have you tried cook?
@iambatman what do you mean
Because x-2 and x+2 don't cancel each other out, would you think answer is C?
yea that seem right
You can cancel out the (5x^2 -1) terms because when you divide, one of those terms will go to the denominator.
I meant have you tried this problem out yourself yet, and used what geerky said?
@iambatman yes i did i just did it wrong and geerky explained it
Cool, well for this problem see if you can cancel some stuff out right away? Do you see anything in numerator and denominator that you can take away/ simplify?
(x-2)
and (x+1)
Nice, now what can you do with the 8 and 4?
divivde by 4
Very good
So what are you left with?
2 and 1
I'm not sure what you mean, can you elaborate?
Ah as in 2 in the numerator and 1 in denominator :)
it would be 8 times (x+2) / 1(x+1
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