Question

tan(-165degrees)

Answer 1

A few things to remember:

1. \(-165^{\circ}\) is in the third quadrant.
2. \(\tan \theta\) is positive when \(\theta\) is in the third quadrant.
3. The reference angle for \(-165^{\circ}\) is \(15^{\circ}\)
4. \(15^{\circ}=\frac{1}{2}(30^{\circ})\)
5. \(\tan\dfrac{\theta}{2} = \dfrac{1-\cos\theta}{\sin\theta}\)

Keeping in mind all of the above, do you think you can find the value of \(\tan(-165^{\circ})\)?

I hope this helps!