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Precalculus
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tan(-165degrees)
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A few things to remember: 1. \(-165^{\circ}\) is in the third quadrant. 2. \(\tan \theta\) is positive when \(\theta\) is in the third quadrant. 3. The reference angle for \(-165^{\circ}\) is \(15^{\circ}\) 4. \(15^{\circ}=\frac{1}{2}(30^{\circ})\) 5. \(\tan\dfrac{\theta}{2} = \dfrac{1-\cos\theta}{\sin\theta}\) Keeping in mind all of the above, do you think you can find the value of \(\tan(-165^{\circ})\)? I hope this helps!
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