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f(y) is a random variable, density function f(y)= [1-(y/2)] from the interval of (0,2) and it is 0 elsewhere. find the mean and variance
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the mean is the integral x * f(x) , or here integral y * f(y)
also called the expected value of the random variable
wow, you're right lol, I completely plank out on this question
so integrate from 0 to 2
since it is zero elsewhere. notice that the definition is
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I got it thanks.
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