someone tell me what i am doing wrong
\[\int\limits_{-1}^{2} (x^3-2x)\]
i got -3/4 but the answer is positive
tell me what i am doing wrong
if its positive go with that
We cannot tell you what you are doing wrong if you don't tell us what you did. The best we can do is tell you the correct way of doing it - but we can't tell you your mistake.
was the answer 3/4 or completely different?
What did you do to get the answer of -3/4? We cannot guess your steps given the final answer you got.
\[F(x)=\frac{x^4}{4}-x^2\] compute \[F(2)-F(-1)\]
Show us your work!
yeah but i want to know why its positive
Here, let me give you hints. - Make sure you are substituting the 2 and substituting the 1 and then subtracting the result from 2 minus the result from -1. Not the other around.
i can tell you added, not subtracted
ok so i got 1/4x^-x^2
(1/4)x^(4)4-x^(2)
then i plug in the 2 and -1 for 2 i got 0
i am telling you my steps
and for -1 i got -3/4 but the answer in the back of my book says its positive 3/4
no i subtracted
Yes, so the answer is 0 - (-3/4) = 3/4, as the book says. You take the upper bound and subtract the lower bound.
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