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Mathematics 29 Online
OpenStudy (el_arrow):

someone tell me what i am doing wrong

OpenStudy (el_arrow):

\[\int\limits_{-1}^{2} (x^3-2x)\]

OpenStudy (el_arrow):

i got -3/4 but the answer is positive

OpenStudy (el_arrow):

tell me what i am doing wrong

OpenStudy (spyro517):

if its positive go with that

OpenStudy (anonymous):

We cannot tell you what you are doing wrong if you don't tell us what you did. The best we can do is tell you the correct way of doing it - but we can't tell you your mistake.

OpenStudy (spyro517):

was the answer 3/4 or completely different?

OpenStudy (anonymous):

What did you do to get the answer of -3/4? We cannot guess your steps given the final answer you got.

OpenStudy (anonymous):

\[F(x)=\frac{x^4}{4}-x^2\] compute \[F(2)-F(-1)\]

OpenStudy (anonymous):

Show us your work!

OpenStudy (el_arrow):

yeah but i want to know why its positive

OpenStudy (anonymous):

Here, let me give you hints. - Make sure you are substituting the 2 and substituting the 1 and then subtracting the result from 2 minus the result from -1. Not the other around.

OpenStudy (anonymous):

i can tell you added, not subtracted

OpenStudy (el_arrow):

ok so i got 1/4x^-x^2

OpenStudy (el_arrow):

(1/4)x^(4)4-x^(2)

OpenStudy (el_arrow):

then i plug in the 2 and -1 for 2 i got 0

OpenStudy (el_arrow):

i am telling you my steps

OpenStudy (el_arrow):

and for -1 i got -3/4 but the answer in the back of my book says its positive 3/4

OpenStudy (el_arrow):

no i subtracted

OpenStudy (anonymous):

Yes, so the answer is 0 - (-3/4) = 3/4, as the book says. You take the upper bound and subtract the lower bound.

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