Question

What is the value of the range of the function f(x)=x^2+2 for the domain value 1/4?

A. Y = 2
B. Y = 2 1/4
C. Y = 2 1/8
D. Y = 2 1/16

Answer 1

domain means all the x-values, and the range is all the y-values.
so
domain =x=1/4
now just plug x=1/4 in the equation to find f(x) and that will be your range

Answer 2

which will produce
\[Y=f(1/4)=(\frac{ 1 }{ 4 })^2+2=1/16+2=33/16=2\frac{ 1 }{ 16 }\]

Answer 3

so what do u do next @sidsiddhartha

Answer 4

ive already solved it D. Y = 2 1/16 thATS the answer ,ok?

Answer 5

thanks

Answer 6

if u have a x value
then just put it in the equation in place of x to get y value

Answer 7

yw!!