Question

Find the critical numbers of the function. (Round your answers to three decimal places.)
s(t)=3t^4+ 4t^3 − 6t^2
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Answer 1

\(s'(t)=4.3t^3 + 4.3t^2-6.2t\)
Solve \(12t^3+12t^2-12t=0\), you will get \(x=0\), \(x=\frac{-1+\sqrt5}{2} \approx 0.618\), \(x=\frac{-1-\sqrt5}{2} \approx -1.618\)