Calculus1
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OpenStudy (emilyjones284):
Rolle's Theorem
f(x)=(x-2)(x-3)(x-4) on [2,4]
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OpenStudy (perl):
did you satisfy the hypotheses of rolle's theorem, first?
OpenStudy (perl):
it must be differentiable on (2,4) and continuous on [2,4] , and it is since it is a polynomial
OpenStudy (emilyjones284):
thats what I don't know how to do
OpenStudy (emilyjones284):
Oh okay I wasn't really sure that it was a polynomial
OpenStudy (perl):
its a polynomial in factored form (linear factors)
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OpenStudy (emilyjones284):
so then plug in 2 and 4
OpenStudy (emilyjones284):
and then take the derivative to find c?
OpenStudy (perl):
first plug in f(2) and f(4)
OpenStudy (perl):
rolles theorem says we must have f(a) = f(b)
OpenStudy (emilyjones284):
okay well I got -2 for f(2) and 0 for f(4) so rolle's theorem does not apply right?
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OpenStudy (perl):
should be zero for f(2)
OpenStudy (perl):
if you plug in 2 , you have (2-2) * whatever = 0
OpenStudy (emilyjones284):
oops i see what I did wrong
OpenStudy (emilyjones284):
so then i just take the derivative and find c right?
OpenStudy (perl):
so now since we have f(2) = f(4) , then there exists a value c inside (2,4) such that f ' (c) = 0
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OpenStudy (perl):
correct, take derivative
OpenStudy (emilyjones284):
the derivative is just 1 right?
OpenStudy (perl):
the derivative should not be 1
OpenStudy (emilyjones284):
but the derivative for each is 1 isn't it?
OpenStudy (perl):
yes but youre using product rule incorrectly
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OpenStudy (emilyjones284):
so then it's just (1)(1)(1)
OpenStudy (emilyjones284):
what am I doing wrong?
OpenStudy (perl):
well
OpenStudy (perl):
you want to use product rule?
OpenStudy (perl):
here is the product rule
( u * v ) ' = u' * v + u * v '
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OpenStudy (emilyjones284):
yes I think
OpenStudy (perl):
we have three factors here though
OpenStudy (emilyjones284):
ohhh I thought i couldve just taken the derivative of each
OpenStudy (perl):
( u * v * w ) ' = u ' * v * w + u * v ' * w + u * v * w '
OpenStudy (perl):
i dont think this is the easiest way to differentiate it , though
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OpenStudy (emilyjones284):
ohh there's an easier way?
OpenStudy (perl):
yes we can expand the original f(x)
OpenStudy (anonymous):
product rule?!
OpenStudy (perl):
technically you could use the product rule :)
OpenStudy (perl):
but will be more work
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OpenStudy (emilyjones284):
so what should I do?
OpenStudy (perl):
f(x)=(x-2)(x-3)(x-4)
= ( x^2 -2x -3x + 6) (x-4)
OpenStudy (perl):
so first expand (x-2)(x-3) using foil
OpenStudy (emilyjones284):
oh and then use the product rule from there?
OpenStudy (perl):
then multiply by x - 4
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OpenStudy (perl):
(x-2)(x-3)(x-4)
= ( x^2 -2x -3x + 6) (x-4)
= ( x^2 - 5x + 6) ( x - 4)
= x^3 - 5x^2 + 6x - 4x^2 +20x - 20
OpenStudy (perl):
f(x) = x^3 -8x^2 + 26x - 20
OpenStudy (perl):
ok? foil then foil again
OpenStudy (emilyjones284):
and then I take the derivative?
OpenStudy (perl):
yes
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OpenStudy (perl):
now its easy to take the derivative
OpenStudy (emilyjones284):
ohh okay thank you so much