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Mathematics
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Confusing. Calculus.
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The function f(x) = (8x-9)e^{5x} has one critical number. Find it.
What did you get for the derivative?
e^5x(40x-37)
Good. Now that implies that \(e^{5x}=0\) or \(40x-37=0\). However, \(e^{5x}>0\) for all real numbers \(x\); hence \(e^{5x}=0\) has no solution. Thus the only part that gives you a solution is \(40x-37=0\). What do you get for x in this case? :-)
37/40
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