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OpenStudy (mateeldaa):
How do I find the exact value for: sin 5pi/3 (pre-cal)
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OpenStudy (anonymous):
sin 5pi/3=sin (2pi-pi/3)=-sinpi/3=-rot3/2
OpenStudy (mateeldaa):
what is rot3/2?
OpenStudy (anonymous):
(sqroot 3)/2
OpenStudy (anonymous):
the answer is -(sqroot 3)/2
OpenStudy (anonymous):
@mateeldaa
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OpenStudy (mateeldaa):
thank you :)
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