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verify the identity cos(2A)=1-2sin^A
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u missed something in Q
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\[\cos2A=1-2\sin^2A\]
\[\sin^2A=1-\cos^2A\]
yeah that's what i meant.
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\[\cos2A=1-2*(1-\cos^2A)\]
what u got after solving this ??
=1-2+2cos^2A =-1+2cos^2A
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